ln(3x)+loge^2(x)=0

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Solution for ln(3x)+loge^2(x)=0 equation: 


Simplifying
ln(3x) + loge2(x) = 0

Remove parenthesis around (3x)
ln * 3x + loge2(x) = 0

Reorder the terms for easier multiplication:
3ln * x + loge2(x) = 0

Multiply ln * x
3lnx + loge2(x) = 0

Multiply e2glo * x
3lnx + e2glox = 0

Reorder the terms:
e2glox + 3lnx = 0

Solving
e2glox + 3lnx = 0

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-3lnx' to each side of the equation.
e2glox + 3lnx + -3lnx = 0 + -3lnx

Combine like terms: 3lnx + -3lnx = 0
e2glox + 0 = 0 + -3lnx
e2glox = 0 + -3lnx
Remove the zero:
e2glox = -3lnx

Divide each side by 'glox'.
e2 = -3g-1no-1

Simplifying
e2 = -3g-1no-1

Combine like terms: -3g-1no-1 + 3g-1no-1 = 0
e2 + 3g-1no-1 = 0

The solution to this equation could not be determined.

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